Question #6fac0

Question

Question #6fac0

1 Answer

Impact of this question

763 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-31T05:17:42

z = 0 and $i^{\frac{1}{3}}$ $i^(1/3)$

Explanation:

$z^{4} + i z = 0$ $z^4 +iz = 0$ can be solved by factoring.
first you can factor out a z
$z (z^{3} + i) = 0$ $z(z^3+i) = 0$
second you find the zeros by finding the values where z = 0.
Since z is multiplied by the term $(z^{3} + i)$ $(z^3+i)$ we know the answer will be true because when z = 0 the other 0 is when $z^{3}$ $z^3$ = -i thus z = cubed root of i which can be written as $i^{\frac{1}{3}}$ $i ^(1/3)$

z = 0 and $i^{\frac{1}{3}}$ $i^(1/3)$

Science

Math

Humanities

... and beyond

Question #6fac0

1 Answer

Explanation:

Related questions

Impact of this question