Question #acd2f

Question

1568 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-31T18:51:30

$b= 2/c+a$

Given: $a/c =(b-a)a/2$

Multiply both sides by $2/a$ :

$2/c =b-a$

Flip the equation:

$b-a= 2/c$

Add a to both sides:

$b= 2/c+a$

Answer 2 · 2017-07-31T18:54:26

$a/c=(b-a)a/2$

$=> b=2/c+a$

We need to isolate $b$ in the formula

$a/c=(b-a)a/2$

$<=>$ Distribute

$a/c=(ba)/2-a^2/2$

$<=>$ Add $a^2/2$ to both sides

$a/c+a^2/2=(ba)/2$

$<=>$ Find a common denominator

$(2a+a^2c)/(2c)=(ba)/2$

$<=>$ Multiply both sides by $2$

$(2a+a^2c)/c=ba$

$<=>$ Divide both sides by $a$

$(2a+a^2c)/(ac)=b$

$<=>$ Simplify

$(2+ac)/c=b$

$<=>$ Simplify
$2/c+a=b$