Question #acd2f

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Answer 1 · 2017-07-31T18:51:30

#b= 2/c+a#

Given: #a/c =(b-a)a/2#

Multiply both sides by #2/a#:

#2/c =b-a#

Flip the equation:

#b-a= 2/c#

Add a to both sides:

#b= 2/c+a#

Answer 2 · 2017-07-31T18:54:26

#a/c=(b-a)a/2#

# => b=2/c+a#

We need to isolate #b# in the formula

#a/c=(b-a)a/2#

#<=># Distribute

#a/c=(ba)/2-a^2/2#

#<=># Add #a^2/2# to both sides

#a/c+a^2/2=(ba)/2#

#<=># Find a common denominator

#(2a+a^2c)/(2c)=(ba)/2#

#<=># Multiply both sides by #2#

#(2a+a^2c)/c=ba#

#<=># Divide both sides by #a#

#(2a+a^2c)/(ac)=b#

#<=># Simplify

#(2+ac)/c=b#

#<=># Simplify
#2/c+a=b#