How do you evaluate $\frac{7}{8} + 4 \frac{1}{2}$ $\frac { 7} { 8} + 4\frac { 1} { 2}$ ?

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Answer 1 · 2017-08-03T17:24:04

$\frac{43}{8}$ $43/8$

$\frac{7}{8} + 4 \frac{1}{2}$ $7/8+4 1/2$

Here, $4 \frac{1}{2}$ $4 1/2$ is nothing other than $4 + \frac{1}{2}$ $4+1/2$ .

The calculation goes this.....

$\frac{7}{8} + 4 \frac{1}{2}$ $7/8+4 1/2$

$= \frac{7}{8} + (4 + \frac{1}{2})$ $=7/8+(4+1/2)$
$= \frac{7}{8} + \frac{4 (2) + 1}{2}$ $=7/8+(4(2)+1)/2$

$= \frac{7}{8} + \frac{8 + 1}{2}$ $=7/8+(8+1)/2$

$= \frac{7}{8} + \frac{9}{2}$ $=7/8+9/2$

$= \frac{7}{8} + \frac{9 (4)}{2 (4)}$ $=7/8+(9(4))/(2(4))$

$= \frac{7}{8} + \frac{36}{8} = \frac{7 + 36}{8} = \frac{43}{8}$ $=7/8+36/8=(7+36)/8=43/8$

Answer 2 · 2017-08-04T13:37:53

$= 5 \frac{3}{8}$ $= 5 3/8$

We can work with the mixed numbers. The values to work with are smaller than if we change to improper fractions.

Add the whole numbers first: then find common denominator

$\frac{7}{8} + 4 \frac{1}{2}$ $7/8 + 4 1/2$

$= 4 \frac{? + ?}{8}$ $= 4 (?+?)/8$

Make equivalent fractions

$= 4 \frac{7 + 4}{8} \leftarrow (\frac{1}{2} = \frac{4}{8})$ $= 4 (7+4)/8" "larr (1/2 = 4/8)$

$= 4 \frac{11}{8}$ $= 4 11/8$

$= 4 + 1 \frac{3}{8} \leftarrow \frac{11}{8} = \frac{8 + 3}{8}$ $= 4+1 3/8" "larr 11/8 = (8+3)/8$

$= 5 \frac{3}{8}$ $= 5 3/8$

How do you evaluate 78+412\frac { 7} { 8} + 4\frac { 1} { 2}?