How do you simplify $\frac{a^{2} + 4 a}{a^{2} - 16}$ $(a^2+4a)/(a^2-16)$ ?

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Answer 1 · 2017-08-04T12:23:17

By factoring the expression: $\frac{a}{a - 4}$ $a/(a-4)$

Your expression can be simplified by factoring

$\frac{a^{2} + 4 a}{a^{2} - 16}$ $(a^2+4a)/(a^2-16)$

$= \frac{a \times (a + 4)}{(a - 4) \times (a + 4)}$ $= (atimes(a+4))/((a-4)times(a+4))$

$= \frac{a}{a - 4}$ $=a/(a-4)$

This is your answer: $\frac{a}{a - 4}$ $a/(a-4)$

How do you simplify a2+4aa2−16(a^2+4a)/(a^2-16)?