Question

Question #1036e

Answer 1

Secondary coil:
Voltage = `1800V`
Current = `1A`

Explanation:

The transformer equation: `(V_p)/(V_s)=(N_p)/(N_s)`, where
`V_p` = voltage through primary coil.
`V_s` = voltage through secondary coil.
`N_p` = number of coils in the primary coil.
`N_s` = number of coils in the secondary coil.

Therefore, we have `120/(V_s)=100/1500`

`V_s=(120*1500)/100=1800V`

Overall power remains constant, although it wouldn't actually, energy would be lost as heat, but forget about that for this.

`P=VI`

`15*120=1800*A_s`

`A_s=(15*120)/1800=1A`

Answer 2

a). A step up transformer will increase the voltage connected in its input side and present it at the output.

Step up factor`="Number of loops in the secondary coil"/"Number of loops in the primary coil"`

and

Output Voltage`="Step up factor"xx"Input Voltage"`

For the given transformer
Step up factor`=1500/100=15`.
Voltage produced in the secondary circuit`=15xx120= 1800 V`.

b). Ignoring resistive losses and losses due to eddy currents

Input Power `=`Output Power

Input Voltage`xx`Current of the input circuit`=`
Output Voltage`xx`Current of the output circuit

`:.120 xx 15 = 1800xxI_o`
`=> I_o=(120 xx 15)/1800=1A`