Question

How do you simplify `\frac { 15} { 4x ^ { 2} } \times \frac { 28x } { 45}`?

Answer 1

See a solution process below:

Explanation:

First, cancel common terms in the numerator and denominator:

`color(red)(cancel(color(black)(15)))/(color(blue)(cancel(color(black)(4)))color(green)(cancel(color(black)(x^2)))x) xx (color(blue)(cancel(color(black)(28)))7color(green)(cancel(color(black)(x))))/(color(red)(cancel(color(black)(45)))3) => 7/(3x)`

Answer 2

`7/(3x)`

Explanation:

`15/(4x^2) *(28x)/45`

`=> (15*28x)/(4x^2*45)`

`=>(15*28x)/(4x*x*45)`

`=>(15*28cancelcolor(red)(x))/(4x*cancelcolor(red)(x)*45)`

`=> (15*28)/(4x*45)`

`=> (15*28)/(4x*3*15)`

`=> (cancelcolor(red)(15)*28)/(4x*3*cancelcolor(red)(15))`

`=> 28/(4x*3)`

`=> (4*7)/(4x*3)`

`=> (cancelcolor(red)(4)*7)/(cancelcolor(red)(4)x*3)`

`=> 7/(x*3)`

`=> 7/(3x)`