#8sinx=4+cosx#
#=>(8sinx-4)^2=cos^2x#
#=>64sin^2x-64sinx+16=1-sin^2x#
#=>65sin^2x-64sinx+15=0#
#=>65sin^2x-39sinx-25sinx+15=0#
#=>13sinx(5sinx-3)-5(5sinx-3)=0#
#=>(5sinx-3)(13sinx-5)=0#
So #sinx =3/5 and sin x= 5/13#
When #sinx =3/5# then #cosx =pmsqrt(1-sin^2x)=pm4/5#
#sinx=3/5 and cosx=4/5# when #x
in " 1st quadrant "
If we put these two values in the given equation we get
#LHS=8sinx=8xx3/4=24/5#
and
#RHS=4+cosx=4+4/5=24/5#
Here #LHS=RHS#
So we can say that #sinx =3/5# satisfies the given equation and this value is an acceptable solution when angle x is in 1st quadrant,
If x is in 2nd quadrant the #sinx =3/5 # but #cosx= -4/5#, these values do not satisfy the given equation
Again
When #sinx =5/13# then #cosx =pmsqrt(1-sin^2x)=pm12/13#
#sinx =5/13 and cosx =12/13# when #x in " 1st quadrant"#
If we put these two values in the given equation we get
#LHS=8sinx=8xx5/13=40/13#
and
#RHS=4+cosx=4+12/13=64/13#
Here #LHS!=RHS#
But if x is in 2nd quadrant the #sinx =5/13 # but #cosx= -12/13#, these values do satisfy the given equation
Hence solution #color(red)(tosinx =3/5" when x is in 1st qudrant") #
and #color(red)(tosinx =5/13" when x is in 2nd quadrant") #