How do you simplify ${(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $(x ^ { - 4} y ^ { - 2} \cdot x ^ { 2} y ^ { - 4} ) ^ { 2}$ ?

Question

How do you simplify ${(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $(x ^ { - 4} y ^ { - 2} \cdot x ^ { 2} y ^ { - 4} ) ^ { 2}$ ?

1 Answer

Impact of this question

1192 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-11T13:38:19

$x^{- 4} \cdot y^{- 12}$ $x^-4*y^-12$

Explanation:

${(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $(x^-4y^-2*x^2y^-4)^2$

$\Rightarrow {(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $=>(x^-4y^-2*x^2y^-4)^2$

$a^{n} \cdot a^{m} = a^{n + m},$ $a^n*a^m=a^(n+m),$ multiplying as per this equation within the brackets.

$\Rightarrow {(x^{- 4} \cdot x^{2} \cdot y^{- 2} \cdot y^{- 4})}^{2}$ $=>(x^-4*x^2*y^-2*y^-4)^2$

$\Rightarrow {(x^{- 4 + 2} \cdot y^{- 2 + - 4})}^{2}$ $=>(x^(-4+2)*y^(-2+ -4))^2$

$\Rightarrow {(x^{- 2} \cdot y^{- 2 - 4})}^{2}$ $=>(x^-2*y^(-2-4))^2$

$\Rightarrow {(x^{- 2} \cdot y^{- 6})}^{2}$ $=>(x^-2*y^-6)^2$

${(x^{n})}^{m} = x^{n \cdot m},$ $(x^n)^m=x^(n*m),$ so ${(x^{n} \cdot y^{p})}^{m} = x^{n \cdot m} \cdot y^{p \cdot m},$ $(x^n*y^p)^m=x^(n*m)*y^(p*m),$ from this we can simply the equation as $:$ $:$

$\Rightarrow x^{- 2 \cdot 2} \cdot y^{- 6 \cdot 2}$ $=>x^(-2*2)*y^(-6*2)$

$\Rightarrow x^{- 4} \cdot y^{- 12}$ $=>x^-4*y^-12$

Science

Math

Humanities

... and beyond

How do you simplify ${(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $(x ^ { - 4} y ^ { - 2} \cdot x ^ { 2} y ^ { - 4} ) ^ { 2}$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify (x−4y−2⋅x2y−4)2(x ^ { - 4} y ^ { - 2} \cdot x ^ { 2} y ^ { - 4} ) ^ { 2}?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify ${(x^{- 4} y^{- 2} \cdot x^{2} y^{- 4})}^{2}$ $(x ^ { - 4} y ^ { - 2} \cdot x ^ { 2} y ^ { - 4} ) ^ { 2}$ ?