How do you solve this system of equations: $y = - 3 x + 1; 5 x - 2 = - y$ $y= - 3x + 1; 5x - 2= - y$ ?

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Answer 1 · 2017-08-14T14:28:07

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$x = \frac{1}{2} y = - \frac{1}{2}$ $x=1/2" " y=-1/2$

$y = - 3 x + 1; 5 x - 2 = - y$ $y=−3x+1;5x−2=−y" "$ this is the same as

$y = - 3 x + 1$ $y=−3x+1"$
$- y = 5 x - 2$ $−y=5x−2" "$ Now add these two equations

$0 = 2 x - 1 \Rightarrow 1 = 2 x$ $0=2x-1" " rArr1=2x" "$ Divide both sides by $2$ $2$

$x = \frac{1}{2}$ $x=1/2" "$ Substitute this into the first equation

$y = - 3 \cdot \frac{1}{2} + 1 \Rightarrow y = - \frac{1}{2}$ $y=-3*1/2+1" "rArry=-1/2$

$x = \frac{1}{2} y = - \frac{1}{2}$ $x=1/2" " y=-1/2$

How do you solve this system of equations: y=−3x+1;5x−2=−yy= - 3x + 1; 5x - 2= - y?