Question #a3f3d

1 Answer
Aug 18, 2017

sin(theta)<0sin(θ)<0

Explanation:

tan(theta)=tan(θ)=opposite //adjacent

So, let's think about triangle in x and y coordinate

opposite = -2
adjacent = 3

so that triangle will be in the fourth part in the x and y coordinate

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hypotenuse= sqrt((3)^2+(-2)^2)=sqrt5(3)2+(2)2=5

So, sin(theta)=-2/sqrt5sin(θ)=25

sin(theta)<0sin(θ)<0