Question #cef51

1 Answer
Aug 19, 2017

See the solution below

Explanation:

L.H.S
=tan2(x)+cos2(x)1sec(x)+sin(x)
=sec2(x)1+cos2(x)1sec(x)+sin(x)

[since tan2(x)=sec2(x)1)]

=sec2(x)1+1sin2(x)1sec(x)+sin(x)
=sec2(x)sin2(x)1sec(x)+sin(x)
={sec(x)+sin(x)}{sec(x)sin(x)}1sec(x)+sin(x)

simplifying we get as
=sec(x)sin(x)=R.H.S