Question

Question #83510

Answer 1

The question is barely visible, but still i'll give you a idea for how to proceed.

Explanation:

Let's suppose you have a trapezoid or trapezium, with one two side length's of parallel sides are given and one angle is given, and you are asked to find the area, perimeter or whatever.

What do you do is just drop a perpendicular

from one vertex to the base containing the given angle so that it forms a triangle.

Now to find the perpendicular height, you take the tangent ( i.e `color(blue)tan(color(red)x)` where `color(red)x` is the angle) of the given angle which is basically `(Opposite)/(Adjacent)`

where (opposite) is the perpendicular height.

Just plug in the values of `color(blue)tan(color(red)x)` and base( Adjacent) by subtracting as shown in the figure and get the value of the perpendicular height. And then you can find anything.

In case of perimeter take the sin of the angle ( i.e `color(blue)sincolor(red)(x)`) which is `(opposite) / (hypotenuse)`.

where (hypotenuse) is the slant length. In other words, the length opposite to the right angle formed by the perpendicular dropped from one of the vertices.

DO THE SAME WITH THE OTHER ANGLE. And then add all the sides you have obtained and you have the perimeter.