Question #cf941

1 Answer
Bdub
Aug 22, 2017

see below

Explanation:

Left Hand Side:
#=>cot x/(csc x+1) * (cscx-1)/(cscx-1) #

#=>(cot x (cscx-1))/(csc^2x-1)#

#=>(cot x (cscx-1))/cot^2x#-Use the property #1+cot^2x=csc^2x#

#=>(cancel(cot x )(cscx-1))/cot^cancel(2)x#

#=>(cscx-1)/cot x#

#:. =# Right Hand Side

Related questions
Impact of this question
808 views around the world
You can reuse this answer
Creative Commons License