Question #cf941

1 Answer
Bdub
Aug 22, 2017

see below

Explanation:

Left Hand Side:
=>cot x/(csc x+1) * (cscx-1)/(cscx-1)

=>(cot x (cscx-1))/(csc^2x-1)

=>(cot x (cscx-1))/cot^2x-Use the property 1+cot^2x=csc^2x

=>(cancel(cot x )(cscx-1))/cot^cancel(2)x

=>(cscx-1)/cot x

:. = Right Hand Side

Related questions
Impact of this question
891 views around the world
You can reuse this answer
Creative Commons License