How do you solve \frac { 7} { x + 1} + \frac { x } { x ^ { 2} - 1} = \frac { 1} { x - 1}7x+1+xx21=1x1?

1 Answer
Aug 28, 2017

x=8/7x=87

Explanation:

First, we can eliminate the denominators. If you notice the denominators, the one denominator (the middle) is the product of the other two.

(x+1)(x-1)=x^2-1(x+1)(x1)=x21

So, we can multiply through by (x+1)(x-1)(x+1)(x1).

7/(x+1)+x/(x^2-1)=1/(x-1) ->7x+1+xx21=1x1

(x+1)(x-1)(7/(x+1)+x/(x^2-1)=1/(x-1)) ->(x+1)(x1)(7x+1+xx21=1x1)

7(x-1)+x=x+17(x1)+x=x+1

Then, we can solve for x.

7(x-1)+x=x+1 ->7(x1)+x=x+1

8x-7=x+1 ->8x7=x+1

7x=87x=8

x=8/7x=87

If you want, you can plug this answer in to check if it is correct.