Question

What is the derivative of `g(t)=(pi)(cos t - 1/t^2)`?

Answer 1

`=pi(2/(t^3) - sin(t))`

Explanation:

remember that `pi` is a constant, so you can just mutiply through:

`g(t) = pi*cos(t) - pi/(t^2) = pi * cos(t) - pi * t^-2`

`(dg)/dt = -pi sin(t) + 2pit^-3`

`=pi(2/(t^3) - sin(t))`