How do you solve #\frac { 8f + 11} { 8} = \frac { 1} { 6}#?

1 Answer
Sep 1, 2017

This can be easily be done using cross multiplication

#(8f + 11)/8 = 1/6#

Multiply the left numerator by the right denominator and set it equal to the right numerator times the left denominator.
top left * bottom right = top right * bottom left, like this:

#(8f + 11) * (6) = (1) * (8)#

Before we multiply out, we can see that both 6 and 8 are divisible by 2, so we can divide both sides by 2 to save us some time.

#(8f + 11) * (3) = (1) * (4)#

Multiply out:

#24f + 33 = 4#

Subtract both sides by 33 to get the #f# terms alone on the left side:

#24f + 33 - (33) = 4 - (33)#
#24f = - 29#

Divide both sides by 24 to get #f# alone on the left side:

#(24f)/24 = -29/(24)#
#f = -29/24#

That fraction can't be reduced, so you're done. If you want to check your answer, you can always plug it back in to the original equation.