How do you solve $40= - 8y - 22$ ?

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Answer 1 · 2017-09-08T04:59:22

$y = -7.75$

$40 = - 8y-22$

$:. 40+22=-8y$

$:. 62=-8y$

$:. 62/(-8)=y$

$:. -7.75=y$

Answer 2 · 2017-09-08T07:44:43

$y =-7 3/4 =-7.75$

Notice that the $y$ -term is negative.
Adding $8y$ to both sides will give a positive $y$ term on the left.

$40color(blue)(+8y)= -8ycolor(blue)(+8y)-22$

Subtracting $40$ from both sides will isolate the $y$ -term.

$40 color(red)(-40) +8y = -22 color(red)(-40)$

$8y = -62$

$y= -62/8 = -31/4$

$y = -7 3/4$

How do you solve 40= - 8y - 22 40= - 8y - 22?