Question

Question #95e4b

Answer 1

This is
Simple harmonic motion (I know u know this ),
For simple harmonic motion Equation is written as
`y=A sin(kx-omegat)`
k=Force constant,
AS , `pi` is multiplied inside.
k=`0.020pi`
`omega`=`4.0(pi)`

k=`(2pi)/Lambda`
So substitute here get lambda

And ,
frequency=`c/lambda`
c is speed of light=`3*10^8`
Intensity=[Power]/area
Intensity is inversely proportional to `r^2`
So,
Intensity=`1/r^2`
So,
divide both of them i.e as 45 and ant 90,
`2.5/I`=`(90/45)^2` here I we have to find

Answer 2

Given equation represents a transverse wave with general equation as

`y(x,t)=Asin ((2pi)/lambda)(x-vt)` .......(1)
where `A` is maximum amplitude, `lambda` is wavelength and `v` wave velocity. Also `-vt` implies velocity in `+x` direction

It also represents Traveling Wave Solution for an ideal string.

it's equivalent form can be written as

`y(x,t)=Asin 2pi(x/lambda-t/T)` ........(2)
where `T` is time period and related to frequency as `f=1/T`

Rewriting given equation in the form as in equation (2) we get

`y(x,t)=5.5sin 2pi(0.010x-2.0t)`

Comparing with (2)

`1/lambda=0.010=>lambda=1/0.010=>lambda=100cm`
`1/T=2.0=>f=2.0Hz`