Question

How do you find the polar coordinate of the following point (-3, -2)?

Answer 1

see below

Explanation:

Use the formulas `x^2+y^2 = r^2` and `tan theta =y/x`

`r^2=(-3)^2+(-2)^2=9+4=13`

`r=sqrt13~~3.606`

`tan theta = y/x=(-2)/-3`

`theta=tan^-1 (2/3)~~0.588`

`:.(r,theta)~~(3.606,0.588)`