How do you solve #-2p - 2= - 5- 2( p + 5)#?

1 Answer
Sep 15, 2017

Refer to explanation

Explanation:

#-2p-2=-5-2(p+5)#

This is the equation ^^

Let's focus on the right side
#-2(p+5)#
First we distribute the brackets/parentheses using this
#a(b+c)=ab+ac#
So using this it would be
#-2*p-2*5#
Then we take #5xx2=10#
So #-2p-10#.

Now we will add in the #-5#.
#-5-2p-10# We will put the variable #p# to the left and the numbers to the right.

#-2p-5-10# which is equal to #-2p-15# Then now you take the equation on the left. (#-2p-2#) From this, it means that

#-2p-2=-2p-15# And this does not make sense.

So, this equation is unsolvable.