How do you solve 5y+9−2(−4y−2)=5(y−1)?

1 Answer
Gaurang B.
Sep 16, 2017

y=−188

Explanation:

5y+9−2(−4y−2)=5(y−1)

To simplify the eqaution,we need to solve the brackets,we need to multiply −2 with (−4y−2) and also 5 with (y−1)

Now, −2⋅(−4y−2) = (−2)(−4y) + (−2)(−2)
Therefore, −2(−4y−2) = 8y+4

Also, 5⋅(y−1)=(5⋅y)−5⋅(1)
Therefore, 5.(y−1)=5y−5

Substituting these values of brackets in equation,we have

5y+9+8y+4=5y−5
Therefore, (5y+8y)+(9+4)=5y−5
Therefore, 13y+13=5y−5
Therefore,(13y−5y)=(−5−13)
Therefore,8y=−18
Thus,y=−188

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