How do you solve #5y + 9- 2( - 4y - 2) = 5( y - 1)#?

1 Answer
Gaurang B.
Sep 16, 2017

#y=-18/8#

Explanation:

#5y + 9 - 2(-4y-2) = 5(y-1)#

To simplify the eqaution,we need to solve the brackets,we need to multiply #-2# with #(-4y-2)# and also #5# with #(y-1)#

Now, #-2*(-4y-2)# = #(-2)##(-4y)# + #(-2)(-2)#
Therefore, #-2##(-4y-2)# = # ##8y +4#

Also, #5*(y-1)#=#(5*y)-5*(1)#
Therefore, #5.(y-1)#=#5y-5#

Substituting these values of brackets in equation,we have

#5y+9+8y+4=5y-5#
Therefore, #(5y+8y)+(9+4)=5y-5#
Therefore, #13y +13=5y-5#
Therefore,#(13y-5y)=(-5-13)#
Therefore,#8y=-18#
Thus,#y=-18/8#

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