Question #57cbb

1 Answer
Sep 16, 2017

#v-10 2/5#

Explanation:

The equation is #v+9/15+ -11#. First, we simplify the #9/15# to #3/5#.
The equation now would be #v+3/5+ -11#. We can convert #-11# to #-11/1# as working on fractions here would be easier.

The equation now would be #v+3/5+ -11/1#. Let's work on the fractions and leave the #v# aside for now. We will make the denominators of both fractions #-11/1# and #3/5#. The lowest common multiple of #1# and #5# is #5#, so we will make the denominators #5#.

#-11/1# will be turned into #-(11*5)/5# and #3/5# will remain.
So the equation (without the #v# still) would be #-(11*5)/5+3/5#.
Since the denominators are the same, we can combine the
fractions like this:
#x/z+y/z=(x+y)/z#
We will combine the fractions now:
#(11*-5+3)/5# Your new equation. <--
Let's solve the top.

#11*-5+3#
Multiply the numbers #-5*11=-55#
#-55+3#
Add the numbers: #-55+3=-52#
So the equation (still without the #v#) would be #(-52)/5#

You have to apply this: #(-x)/y=-x/y# See where the negative sign will be?
So, in this case, #(-52)/5=-52/5#.
The whole equation would be #v=-52/5# or #v=-10 2/5# if you change it to a mixed number.