$\int \frac{{log}_{10} x}{x} d x$ $int(log_10x)/xdx$ ?

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$\int \frac{{log}_{10} x}{x} d x$ $int(log_10x)/xdx$ ?

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Answer 1 · 2017-09-17T23:31:44

It is

$\int \frac{\frac{log x}{log 10}}{x} d x = \frac{1}{log 10} \cdot \int (\frac{log x}{x}) d x = \frac{1}{2 \cdot log 10} \cdot {(log x)}^{2}$ $int (logx/log10)/(x) dx=1/(log10)*int(logx/x) dx= 1/(2*log10)*(logx)^2$

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$\int \frac{{log}_{10} x}{x} d x$ $int(log_10x)/xdx$ ?

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$\int \frac{{log}_{10} x}{x} d x$ $int(log_10x)/xdx$ ?