Question

A minor league baseball team plays 11 games in a season. If the team won 15 more than three times as many games as they lost. How many wins and losses did the team have?

Answer 1

5 wins and 10 losses

Explanation:

Let the number of wins be `x` and the number of losses be `y`.

Assuming there were no ties,the total number of games played by team would be equal to sum of number of losses and number of wins.

Therefore, (1) `x+y=15`
Also,the team won 15 more than three times as many games as they lost.
Thus,(2) `3x=15+3y`

Equations (1) and (2) are linear equations in variables `x` and `y`
and can be solved by method of substitution.

From (1) ,`x=15-y`

Substituting `x=15-y` in (2),
`3(15-y)=15+3y`
`45-3y=15+3y`
`45-15=3y+3y`
`30=6y`
Therefore,`y=5`

From (1),`x=15-y`
Substituting `y=5` in above equation,
`x=15-5`
Thus, `x=10`

Thus, the team had 10 wins and 5 losses.