x-3(x-y)-4-5(y+2x)+7x−3(x−y)−4−5(y+2x)+7
For simplifying the given term,we need to solve the brackets.
The first bracket can be solved by multiplying -3−3 with (x-y)(x−y) and the second bracket can be solved by multiplying -5−5 with (y+2x)(y+2x)
Now,-3(x-y)=(-3)x-(-3)y−3(x−y)=(−3)x−(−3)y
Thus,-3(x-y)=-3x+3y−3(x−y)=−3x+3y
Similarly,-5(y+2x)=(-5)y+(-5)2x−5(y+2x)=(−5)y+(−5)2x
Therefore,-5(y+2x)=-5y-10x−5(y+2x)=−5y−10x
Placing these values in the term,we have
x-3x+3y-4-5y-10x+7x−3x+3y−4−5y−10x+7 , which is
x-3x-10x+3y-5y-4+7x−3x−10x+3y−5y−4+7 , which is
-12x-2y+3−12x−2y+3
Therefore, x-3(x-y)-4-5(y+2x)+7=-12x-2y+3x−3(x−y)−4−5(y+2x)+7=−12x−2y+3