How do you solve #1/3 - x/7 = 14/54#?

2 Answers
Sep 18, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(1/3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#1/3 - color(red)(1/3) - x/7 = 14/54 - color(red)(1/3)#

#0 - x/7 = 14/54 - (18/18 xx color(red)(1/3))#

#-x/7 = 14/54 - 18/54#

#-x/7 = (14 - 18)/54#

#-x/7 = -4/54#

#-x/7 = -2/27#

Now, multiply each side of the equation by #color(red)(-7)# to solve for #x# while keeping the equation balanced:

#color(red)(-7) xx x/-7 = color(red)(-7) xx -2/27#

#cancel(color(red)(-7)) xx x/color(red)(cancel(color(black)(-7))) = 14/27#

#x = 14/27#

Sep 18, 2017

This is how we do it .

Explanation:

#1/3-x/7=14/54#

Take #-x/7# in the right so it will become #+x/7# . And take #14/54#on the left and it will become #-14/54#.
:. #1/3-14/54=x/7#

Then first solve #1/3-14/54# so , to solve you need to make the denominator same this is done by taking the LCM of #3#and #54#. That is 54 .

:. #1xxcolor(red)18##/##3xxcolor(red)18# #-# #14xxcolor(red)1##/##54xxcolor(red)1#
#:.# #18/54##-##14/54# #=x/7#
#:.# #4/54=x/7#
#:.# #4/54xx7##=x#