Question

How do you evaluate `(4n - 4) ( 4n ^ { 2} + 2n + 2)`?

Answer 1

`(-64n^3-32n^2-32)`

Explanation:

`(4n-4)(4n^2+2n+2)`

Use the distributive property!
Distribute the first set of parenthesis into the second set (make sure to distribute the `4n` to all of the numbers into the second set of parenthesis AND distribute the `-4` as well:

`4n` first:

`(-4)(16n^3+8n^2+8n)`

Now the `-4`:

`(-64n^3-32n^2-32)`

You could solve for the `n`, but there would be `3` answers. You would just solve it like a cubic. If you need the values for `n`, just notify me, and I will further elaborate. But off of your question, I think that's all you needed to do for your sake.