How do you solve $8 r (3 t - 2 r) - 3 r (s + 2 t) - r t$ $8r(3t-2r)-3r(s+2t)-rt$ ?

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Answer 1 · 2017-09-19T04:56:04

$- 16 r^{2} + 17 r t - 3 r s$ $-16r^2+17rt-3rs$

You definitely cannot solve for anything, it is an expression, not an equation. I hope you meant to just simplify, if so, here you go!

$8 r (3 t - 2 r) - 3 r (s + 2 t) - r t$ $8r(3t-2r)-3r(s+2t)-rt$

First, distribute everything to remove the parentheses:

$(24 r t - 16 r^{2}) + (- 3 r s - 6 r t) - r t$ $(24rt-16r^2)+(-3rs-6rt)-rt$

Combine like terms:

$- 16 r^{2} + (24 r t - 6 r t - r t) - 3 r s$ $-16r^2 +(24rt-6rt -rt) -3rs$

$- 16 r^{2} + 17 r t - 3 r s$ $-16r^2+17rt-3rs$

How do you solve 8r(3t−2r)−3r(s+2t)−rt8r(3t-2r)-3r(s+2t)-rt?