How do you find the coefficient of #a# of the term #ax^8y^6# in the expansion of the binomial #(x^2+y)^10#?

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Answer 1 · 2017-09-21T08:00:17

#(a + b)^10 = (10C0)a^10b^0 + (10C1)a^9b^1 + (10C2)a^8b^2 + ...#

Continuing to the 7th term we have:

#(10C6)a^4b^6#

With #a => x^2 and b => y# we get:

#(10C6)(x^2)^4(y^6)#

i.e. #(10C6)x^8y^6#

so, coefficient is 10C6 = 210

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