Question #df58e

Question

Question #df58e

1 Answer

Impact of this question

991 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-21T10:30:44

Displacement is $\approx 24.233 m$ $~~24.233m$

Explanation:

The first thing to do is to calculate the acceleration of the train. We do that by using the acceleration formula, which states
$a = \frac{u - v}{t}$ $a=(u-v)/t$ , where $a$ $a$ is the acceleration, $v$ $v$ is the initial velocity in m/s, $u$ $u$ is the final velocity in m/s and $t$ $t$ is the time taken in seconds. Looking at our question, we see that $t = 7.94$ $t=7.94$ , $u = 12.3864 and v = 0$ $u=12.3864 and v=0$ (since the train starts from rest). Plug these into the formula, and we get

$a = \frac{12.3864 - 0}{7.94}$ $a=(12.3864-0)/7.94$
$a = \frac{12.3864}{7.94}$ $a=12.3864/7.94$
$a = \frac{39}{25} = 1.56 m s^{- 2}$ $a=39/25=1.56ms^-2$

The last thing to do is to calculate the distance travelled. To do that we use this formula (which works with displacement as long as the displacement = distance, as it does in this question):
$s = u t + \frac{a t^{2}}{2}$ $s=ut+ (at^2)/2$ , where $s$ $s$ is the distance or displacement in metres, $u$ $u$ is the initial velocity in m/s, $t$ $t$ is the time in seconds and $a$ $a$ is the acceleration in m/ $s^{2}$ $s^2$ . Looking at our equation, we see that $t = 5.57388, u = 0 and a = 1.54$ $t=5.57388, u=0 and a=1.54$ . Plug these into our equation to get

$s = 0 \cdot 5.57388 + \frac{1.56 \cdot {5.57388}^{2}}{2}$ $s=0*5.57388 +(1.56*5.57388^2)/2$
$s = \frac{1.56 \cdot {5.57388}^{2}}{2}$ $s=(1.56*5.57388^2)/2$

$s = \frac{48.46629568}{2}$ $s=48.46629568/2$

$s \approx 24.233 m$ $s~~24.233m$ , the total displacement of the train.

http://www.dummies.com/education/science/physics/how-to-calculate-time-and-distance-from-acceleration-and-velocity/

I hope I helped!

Science

Math

Humanities

... and beyond

Question #df58e

1 Answer

Explanation:

Related questions

Impact of this question