A baseball goes from zero to 41 m/s in 0.238 s. What is its average acceleration?

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Answer 1 · 2017-09-21T14:17:23

average acceleration of the baseball is $172.269ms^-2$

Acceleration of baseball is the change in velocity in a given interval of time divided by the time taken.

$a=(v_2-v_1)/t$ .

where,

$v_1$ is the initial velocity,

$v_2$ is the final velocity and

$t$ is the time taken (or the time interval in which velocity changes from initial velocity to the final velocity)

Therefore ,
$v_1=0ms^-1$ .
$v_2=41ms^-1$ .

$t=0.238s$

SUBSTITUTING THE VALUES IN THE EQUATION :

$a=(41-0)/0.238ms^-2$
$a=172.269ms^-2$

Here we are provided with the initial and final velocity only so that acceleration we find is the average acceleration of the baseball .