Question

Question #1dd24

Answer 1

`6 xx 10^-5m`

Explanation:

To be able to find the wavelength we can use the wave equation. It is `c=flambda`
Where,
`c` is the speed of light = `3.00 xx 10^8m.s^-1`
`f` is frequency of the electromagnetic radiation
`lambda` is the wavelength

when rearranging this equation to solve for `lambda`, we get `lambda=c/f`.
`=(3.00 xx 10^8)/(5.00 xx 10^12)`
`= 6xx10^-5m`
For the second question we need to look at the electromagnetic radiation spectrum.

If you go back and have a look, both the wavelength and frequency correspond to the infra-red (IR).

Therefore, the answer is infra-red(IR).