Question #f1191

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Answer 1 · 2017-09-21T22:51:50

#c=(5-b)/(3ab)#

#3abc+b=5#

Subtract #b# from both sides:

#3abc+b-b=5-b#

#3abc=5-b#

Divide both sides by 3ab:

#(3abc)/(3ab)=(5-b)/(3ab)#

#c=(5-b)/(3ab)#

You could split the fraction into 2 fractions and cancel a b term but I think the above is sufficient.