Question #f1191

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Answer 1 · 2017-09-21T22:51:50

$c=(5-b)/(3ab)$

$3abc+b=5$

Subtract $b$ from both sides:

$3abc+b-b=5-b$

$3abc=5-b$

Divide both sides by 3ab:

$(3abc)/(3ab)=(5-b)/(3ab)$

$c=(5-b)/(3ab)$

You could split the fraction into 2 fractions and cancel a b term but I think the above is sufficient.