How do you solve $25^ { 1- 3n } = 625^ { - n - 1}$ ?

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Answer 1 · 2017-09-22T05:05:53

$n=3$

Rewrite the expression by finding the same base on both sides

$25^(1-3n)=625^(-n-1)$

$rArr5^(2(1-3n))=5^(4(-n-1))$

$rArr5^(2-6n)=5^(-4n-4)$

Equate the powers to solve for $n$

$2-6n=-4n-4$

$2n=6$

$n=3$

How do you solve 25^ { 1- 3n } = 625^ { - n - 1}25^ { 1- 3n } = 625^ { - n - 1}?