How do you solve 25^ { 1- 3n } = 625^ { - n - 1}2513n=625n1?

1 Answer
Sep 22, 2017

n=3n=3

Explanation:

Rewrite the expression by finding the same base on both sides

25^(1-3n)=625^(-n-1)2513n=625n1

rArr5^(2(1-3n))=5^(4(-n-1))52(13n)=54(n1)

rArr5^(2-6n)=5^(-4n-4)526n=54n4

Equate the powers to solve for nn

2-6n=-4n-426n=4n4

2n=62n=6

n=3n=3