How do you evaluate #5^ { 2} \cdot 5^ { - 6}#?

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Answer 1 · 2017-09-25T12:59:59

#1/625#

We will apply this rule:

#x^y*x^z=x^(y+z)#

#5^-6*5^2=5^(2-6)=5^(-4)#

Then we use this:

#x^-y=1/(x^y)#

Therefore, #5^-4# is the same as #1/(5^4)#
#5^4=625#

The fraction will be #1/625#.