Question #0f255

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Question #0f255

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Answer 1 · 2017-09-30T19:03:48

1.02*10^26 $1.02 \cdot 10^{26}$ $1.02*10^26$ atoms of Ca

Explanation:

$\frac{6.78 \cdot 10^{3} grams of Ca}{1} \cdot (\frac{1 mole of Ca}{40.078 g of Ca}) \cdot (\frac{6.0221 \cdot 10^{23} atoms of Ca}{1 mole of Ca}) = 101875936923000149708069264.93338 atoms of Ca$ $(6.78*10^3 "grams of Ca")/1*((1 "mole of Ca")/(40.078 "g of Ca"))*((6.0221*10^23 "atoms of Ca")/(1 "mole of Ca"))=101875936923000149708069264.93338 "atoms of Ca"$
Three significant digits. so the answer is...
102000000000000000000000000 atoms of Ca

And in correct scientific notation...
$1.02 \cdot 10^{26}$ $1.02*10^26$ atoms of Ca

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Question #0f255

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