How do you solve #p=(r+2s)/t# for #r#?

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Answer 1 · 2017-10-01T11:53:09

#r=pt-2s#

First, we multiply both sides by #t#:

From
#p=(r+2s)/t# to #pt=r+2s#

Then, we subtract #2s# from both sides:

#r+2scolor(blue)-color(blue)2color(blue)s=ptcolor(blue)-color(blue)2color(blue)s#
#r=pt-2s#

Answer 2 · 2017-10-01T11:54:54

#r=pt-2s#

If
#color(white)("XXX")p=(r+2s)/t#
then

after multiplying both sides by #t#
#color(white)("XXX")pt=r+2s#

and then subtracting #2s# from both sides
#color(white)("XXX")pt-2s=r#
...or using the reflexive property for equality: #r=pt-2s#