Question

Question #f1610

Answer 1

`3(x+3)(x-1)` (if you meant `3x^2+6x-9`)

Explanation:

First, take out the 3 as it is the highest common factor.

`3(x^2+2x+3)`
then factorise looking for numbers that multiply to 3 and add to 2. This is impossible to do with real numbers, as the equation has no real roots - it doesn't intercept the x-axis. See graph below.

#3(x+2 graph{x^2+2x+3 [-10, 10, -2, 10]}

If you meant `3x^2+6xcolor(red)(-)9` then it factorises as `3(x+3)(x-1)`