Find two numbers that multiply to negative 5 and add to 6.
Since #5# is a prime number, its only factors are #5 and 1#.
If one of these is negative then they'll multiply to #-5#. Unfortunately, #-5 xx 1 = 5# but #-5+1=-4# and not #6#
Also #5 and -1# add to #4# and not #6#... this means it can't be factorised so we will have to use completing the square or the quadratic formula.
First, divide 6 by two and square it with #x#:
#(x+3)^2# this would expand to #x^2+6x+9# which is right except for the #9# - we need #-5# so we subtract #14#.
#(x+3)^2-14=0#
now solve for #x#:
#(x+3)^2=14#
#x+3=±sqrt14#
#x=-3±sqrt14#