Question #24009

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Answer 1 · 2017-10-03T13:49:16

38.51 mi/h

Average velocity of the car is the ratio of total distance traveled by the car to the velocity of the car.

$v=S/T$

where,

v is the velocity (average) of the car ,

S is the total distance traveled by the car ,

T is the total time taken .

Total distance traveled S= $13.6+23.8+43.1=80.5$ miles

Time taken to cross first 13.6 miles:

$S_1=13.6$ mi

$v_1=55$ mi/h

$S=v*t$
$t_1=S_1/v_1$

$t_1=13.6/55$

$t_1=0.247$ h

Similarly $t_2=S_2/v_2$

$t_2=25.8/48$

$t_2=0.537$ h

$t_3=S_3/v_3$

$t_3=43.1/33$

$t_3=1.306$ h

Therefore total time taken $T=t_1+t_2+t_3$

$T=0.247+0.537+1.306$

$T=2.09$ h

Hence from this data we can find average velocity .

$v=S/T$

$v=80.5/2.09$

$color(red)("AVERAGE VELOCITY ")$

$v=38.51$ mi/h