Question #eacbf

1 Answer
sans
Oct 4, 2017

KE = 5.23 *10^-225.23⋅10−22 J

Explanation:

Given:
v = 150 m/s
m = 28 g/mol

- Solving for the mass of the molecule in kg

m = 28 g/mol = 0.028 kg / mole = 0.028 kg / 6.022 * 10^236.022⋅1023 molecules = 4.65 * 10^-264.65⋅10−26 kg/ molecule

- Solving for the kinetic energy (KE)

KE = 1/2 mv^212mv2 = 1/2 (4.65 * 10^-26 kg) (150 m/s)^2 = 5.23 *10^-2212(4.65⋅10−26kg)(150ms)2=5.23⋅10−22 J

Related questions
Impact of this question
1101 views around the world
You can reuse this answer
Creative Commons License