How do you evaluate $\frac{m - 1}{2 m^{2} - 10 m + 12} - \frac{m - 5}{2 m^{2} - 10 m + 12}$ $\frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}$ ?

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Answer 1 · 2017-10-05T08:07:53

$\frac{2}{(m - 3) (m - 2)}$ $2/((m-3)(m-2)$

Since the denominators in both fractions are the same, we can combine them into one fraction

$\frac{m - 1}{2 m^{2} - 10 m + 12} - \frac{m - 5}{2 m^{2} - 10 m + 12}$ $(m-1)/(2m^2-10m+12) - (m-5)/(2m^2-10m+12)$

$= \frac{(m - 1) - (m - 5)}{2 m^{2} - 10 m + 12}$ $=((m-1)-(m-5))/(2m^2-10m+12)$

Solving for the numerator

$\frac{m - 1 - m + 5}{2 m^{2} - 10 m + 12}$ $(m-1-m+5)/(2m^2-10m+12)$

$= \frac{4}{2 m^{2} - 10 m + 12}$ $=4/(2m^2-10m+12)$

Simplify the denominator....

$= \frac{4}{2 (m - 3) (m - 2)}$ $=4/(2(m-3)(m-2)$

Divide numerator and denominator by 2

$= \frac{2}{(m - 3) (m - 2)}$ $=2/((m-3)(m-2)$

Hope I helped you in this problem!
Cheers!

How do you evaluate \frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}m−12m2−10m+12−m−52m2−10m+12\frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}?