How do you solve #\frac{14}{12}=\frac{1}{10^{6}}+\frac{x}{10}#?

2 Answers
Oct 6, 2017

#x = (35(10^5)-3)/(3(10^5))#

This is how I would answer the equation, I'm not sure how simplified you want it.

Explanation:

#14/12 = 1/10^6 + x/10#

Simplify both sides
#7/6 = 10^-6+(10^-1)x#

Take out the #10^-1# and move to the other side
#10*7/6 = 10^-5 + x#

Simplify the #70/6# and move the #10^-5# over
#35/3 - 1/10^5 = x#

Multiply each fraction by each other's denominator to give the same denominator
#(35/3(10^5))/(3(10^5)) - 3/(3(10^5)) = x#

Now just subtract!
#x = (35(10^5)-3)/(3(10^5))#

Oct 6, 2017

#x ~~ 11.6667#

Explanation:

If you have an equation which has fractions, you can get rid of them immediately by multiplying by the LCD to cancel the denominators.

#1/10^6+x/10 =12/10" "larr 12/10 =7/6#

#LCD = color(blue)(6 xx 10^6)#

#(color(blue)(6 xx 10^6)xx1)/10^6 +(color(blue)(6 xx 10^6)xx x)/10 = (color(blue)(6 xx 10^6)xx7)/6#

Simplify both sides:

#(color(blue)(6xx cancel10^6)xx1)/cancel10^6 +(color(blue)(6 xx 10^(cancel6 5))xx x)/cancel10 = (color(blue)(cancel6^1 xx 10^6)xx7)/cancel6#

This leads to:

#6+6xx10^5xx x=7xx10^6#

#" "6xx10^5xx x=7xx10^6 -6" "larr# now isolate #x#

#x =(7xx10^6 -6)/(6xx10^5#

#x = (7xx10^6)/(6xx10^5)-cancel6/(cancel6xx10^5)#

#x = 70/6 -1xx10^-5#

#x ~~11.6667#