How do you simplify $(4 r^{2} + 4 r + 3) (3 r^{2} - 5 r - 3)$ $(4r ^ { 2} + 4r + 3) ( 3r ^ { 2} - 5r - 3)$ ?

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How do you simplify $(4 r^{2} + 4 r + 3) (3 r^{2} - 5 r - 3)$ $(4r ^ { 2} + 4r + 3) ( 3r ^ { 2} - 5r - 3)$ ?

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Answer 1 · 2017-10-06T03:37:35

$12 r^{2} - 8 r^{3} - 23 r^{2} - 27 r - 9$ $12r^2−8r^3−23r^2−27r−9$

Explanation:

$(4 r^{2}) (3 r^{2}) + (4 r^{2}) (- 5 r) + (4 r^{2}) (- 3) + (4 r) (3 r^{2}) + (4 r) (- 5 r) + (4 r) (- 3) + (3) (3 r^{2}) + (3) (- 5 r) + (3) (- 3)$ $(4r^2)(3r^2)+(4r^2)(−5r)+(4r^2)(−3)+(4r)(3r^2)+(4r)(−5r)+(4r)(−3)+(3)(3r^2)+(3)(−5r)+(3)(−3)$
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into:
$12 r^{2} - 8 r^{3} - 23 r^{2} - 27 r - 9$ $12r^2−8r^3−23r^2−27r−9$

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How do you simplify $(4 r^{2} + 4 r + 3) (3 r^{2} - 5 r - 3)$ $(4r ^ { 2} + 4r + 3) ( 3r ^ { 2} - 5r - 3)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you simplify (4r2+4r+3)(3r2−5r−3)(4r ^ { 2} + 4r + 3) ( 3r ^ { 2} - 5r - 3)?

1 Answer

Explanation:

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How do you simplify $(4 r^{2} + 4 r + 3) (3 r^{2} - 5 r - 3)$ $(4r ^ { 2} + 4r + 3) ( 3r ^ { 2} - 5r - 3)$ ?