What is the equation of the line that passes through (8,4) and parallel to #4x - y = 8#?

2 Answers
Oct 9, 2017

4x-y=28

Explanation:

to be parallel with #y=4x-8#, it is #y=4x+a#.
(8,4)=>#32+a=4#,#a=-28# so #y=4x-28,4x-y=28#

Oct 9, 2017

#y=4x-28#

Explanation:

#4x-y=8# is the same as: #y=4x-8#

So the slope is #4# and the y-intercept is #-8#

The equation of the line we are trying to find is parallel to this line, and parallel lines have equivalent slopes.

So we need a line with the equation:

#y=4x+b# where #b# is the y-intercept of this parallel line.

Since the line goes through #(8,4)# we can plug in those values for x and y:

#(4)=4(8)+b#

#4=32+b#
#-28=b#

So equation is: #y=4x-28#