How do you add $\frac{- 5}{9 v^{3} w^{2}} + \frac{3}{4 v^{2} w}$ $\frac { - 5} { 9v ^ { 3} w ^ { 2} } + \frac { 3} { 4v ^ { 2} w }$ ?

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Answer 1 · 2017-10-09T12:08:31

$= \frac{- 20 + 27 v w}{36 v^{3} w^{2}}$ $=(-20+27vw)/(36v^3w^2)$

We would sum the fractions by finding the LCM of their denominators, that's

$L C M (9 v^{3} w^{2}; 4 v^{2} w) = 36 v^{3} w^{2}$ $LCM(9v^3w^2;4v^2w)=36v^3w^2$

and reduce them to one fraction:

$\frac{- 5 (4) + 3 (9 v w)}{36 v^{3} w^{2}}$ $(-5(4)+3(9vw))/(36v^3w^2)$

$= \frac{- 20 + 27 v w}{36 v^{3} w^{2}}$ $=(-20+27vw)/(36v^3w^2)$

How do you add \frac { - 5} { 9v ^ { 3} w ^ { 2} } + \frac { 3} { 4v ^ { 2} w }−59v3w2+34v2w\frac { - 5} { 9v ^ { 3} w ^ { 2} } + \frac { 3} { 4v ^ { 2} w }?