How do you divide (4x ^ { 3} - 12x + 8) \div ( x - 3)?

1 Answer
Oct 9, 2017

4x^2 +12x +4 Remainder:   (80)/(x-3)

Explanation:

color(white)(xxxxxxxxxx)ul(4x^2+ color(white)(xxxxxx) 12x + 24 color(white)(xx)
color(white)(xxxxx) x−3 | 4x^3 color(white)(xxxxxx) -12x+8
color(white)(xxxxxxxxx) ul(-4x^3+12x^2 color(white)(xxxxxx))
color(white)(xxxxxxxxxxxxxxx)12x^2-12x
color(white)(xxxxxxxxxxxxxx) ul(-12x^2+36x color(white)(xxxx))
color(white)(xxxxxxxxxxxxxxxxxxxx) 24x+color(white)(x)8
color(white)(xxxxxxxxxxxxxxxxxxx) ul(-24x+72color(white)(x))
color(white)(xxxxxxxxxxxxxxxxxxxxxxxxx)80

Answer:
4x^2 +12x +4

Remainder:   (80)/(x-3)