How do you divide #(4x ^ { 3} - 12x + 8) \div ( x - 3)#?

1 Answer
Oct 9, 2017

#4x^2 +12x +4# Remainder: #  (80)/(x-3)#

Explanation:

#color(white)(xxxxxxxxxx)ul(4x^2+ color(white)(xxxxxx) 12x + 24 color(white)(xx)#
#color(white)(xxxxx) x−3 | 4x^3 color(white)(xxxxxx) -12x+8#
#color(white)(xxxxxxxxx) ul(-4x^3+12x^2 color(white)(xxxxxx))#
#color(white)(xxxxxxxxxxxxxxx)12x^2-12x #
#color(white)(xxxxxxxxxxxxxx) ul(-12x^2+36x color(white)(xxxx))#
#color(white)(xxxxxxxxxxxxxxxxxxxx) 24x+color(white)(x)8#
#color(white)(xxxxxxxxxxxxxxxxxxx) ul(-24x+72color(white)(x))#
#color(white)(xxxxxxxxxxxxxxxxxxxxxxxxx)80#

Answer:
#4x^2 +12x +4#

Remainder: #  (80)/(x-3)#