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Question #efa64

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Oct 10, 2017

67.2 L

Explanation:

You have 96 g of $O_{2}$ $O_2$ .
1 mol of $O_{2}$ $O_2$ = 32 g
96 g of $O_{2}$ $O_2$ = 96/32 mol of $O_{2}$ $O_2$
$= 3$ $=3$ mol of $O_{2}$ $O_2$

1 mol of gas occupies 22.4L at STP
3 mol of $O_{2}$ $O_2$ occupies $3 \times 22.4$ $3\times22.4$ L at STP

The volume occupied by 96 g of $O_{2}$ $O_2$ at STP = 67.2 L

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