How do you simplify $\frac{2}{2 a} + \frac{4 a}{6 a + 12}$ $\frac { 2} { 2a } + \frac { 4a } { 6a + 12}$ ?

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Answer 1 · 2017-10-10T19:25:46

$\frac{2 a^{2} + a + 2}{a^{2} + 2 a}$ $(2a^2+a+2)/(a^2+2a)$

Start by factoring every numerator and denominator:

$\frac{2}{2 (a)} + \frac{2 (2 a)}{6 (a + 2)}$ $2/(2(a))+(2(2a))/(6(a+2))$

Divide away the $2$ $2$ ’s in both fraction:

$cancel(2)/(cancel(2)(a))+(cancel(2)(2a))/(cancel(2)*(3)(a+2))$

So:

$1/a+(2a)/(a+2)$

Get a common denominator of $a^2+2a$

$(a+2)/(a^2+2a)+(2a^2)/(a^2+2a)=(2a^2+a+2)/(a^2+2a)$

How do you simplify \frac { 2} { 2a } + \frac { 4a } { 6a + 12}22a+4a6a+12\frac { 2} { 2a } + \frac { 4a } { 6a + 12}?