How do you simplify $(x^{3} - 4 x^{2} - 17 x + 6) \div (x - 3)$ $(x^3 - 4x^2 - 17x +6) \divide (x-3)$ ?

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How do you simplify $(x^{3} - 4 x^{2} - 17 x + 6) \div (x - 3)$ $(x^3 - 4x^2 - 17x +6) \divide (x-3)$ ?

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Answer 1 · 2017-10-10T19:48:47

$x^{2} - x - 20 - \frac{54}{x - 3}$ $x^2-x-20-54/(x-3)$

Explanation:

You can use synthetic division:

Our factor is $(x - 3)$ $(x-3)$ so our root is $+ 3$ $+3$

$3 ⌋$ $3__|$ $1$ $1$ $0$ $color(white)(0)$ $- 4$ $-4$ $0$ $color(white)(0)$ $- 17$ $-17$ $0$ $color(white)(0)$ $6$ $6$
+ $0$ $color(white)(0)$ $↓$ $darr$ $00$ $color(white)(00)$ $3$ $3$ $00$ $color(white)(00)$ $- 3$ $-3$ $0$ $color(white)(0)$ $- 60$ $-60$
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How do you simplify $(x^{3} - 4 x^{2} - 17 x + 6) \div (x - 3)$ $(x^3 - 4x^2 - 17x +6) \divide (x-3)$ ?

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Explanation:

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How do you simplify (x3−4x2−17x+6)÷(x−3)(x^3 - 4x^2 - 17x +6) \divide (x-3)?

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Explanation:

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How do you simplify $(x^{3} - 4 x^{2} - 17 x + 6) \div (x - 3)$ $(x^3 - 4x^2 - 17x +6) \divide (x-3)$ ?